50 lines
2.2 KiB
Python
50 lines
2.2 KiB
Python
'''
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Onionr - P2P Microblogging Platform & Social network
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OnionrUtils offers various useful functions to Onionr. Relatively misc.
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'''
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'''
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>.
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'''
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# Misc functions that do not fit in the main api, but are useful
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import getpass, sys, requests, configparser, os
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class OnionrUtils():
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'''Various useful functions'''
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def __init__(self):
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return
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def printErr(self, text='an error occured'):
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'''Print an error message to stderr with a new line'''
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sys.stderr.write(text + '\n')
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def localCommand(self, command):
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'''Send a command to the local http API server, securely. Intended for local clients, DO NOT USE for remote peers.'''
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config = configparser.ConfigParser()
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if os.path.exists('data/config.ini'):
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config.read('data/config.ini')
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else:
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return
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requests.get('http://' + open('data/host.txt', 'r').read() + ':' + str(config['CLIENT']['PORT']) + '/client/?action=' + command + '&token=' + config['CLIENT']['CLIENT HMAC'])
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def getPassword(self, message='Enter password: '):
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'''Get a password without showing the users typing and confirm the input'''
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# Get a password safely with confirmation and return it
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while True:
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print(message)
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pass1 = getpass.getpass()
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print('Confirm password: ')
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pass2 = getpass.getpass()
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if pass1 != pass2:
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print("Passwords do not match.")
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input()
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else:
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break
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return pass1 |